Question

encontre as raízes a x elevado a quadrado -7x - 18 = 0



obs precisar de cálculo ​

Answer 1

por delta e bhaskara:

${x}^{2} - 7x - 18 = 0 \\ Δ = {( - 7)}^{2} - 4 \times 1 \times ( - 18) \\ Δ = 49 + 72 = 121 \\ x = \frac{ - ( - 7) \frac{ + }{} \sqrt{121} }{2 \times 1} \\ x = \frac{7 \frac{ + }{} 11}{2} \\ x = 9 \: ou \: x = - 2$

Answer 2

Olá ^^

x² - 7x - 18 = 0

A= 1

B= - 7

C= - 18

∆= b² - 4ac

∆= ( - 7)² - 4 • 1 • ( - 18)

∆= 49 + 72

∆= 121

x= - b ± √∆ / 2a

x= - ( - 7) ± √121 / 2 • 1

x'= 7 + 11/2 = 18/2 = 9

x''= 7 - 11/2 = - 4/2 = - 2

S= ( - 2 , 9)