Question

encontre as raízes

6x² + x -1 = 0

3x² -7x +2 = 0​

Answer 1

Resposta:

Abaixo

Explicação passo-a-passo:

a)

$6x^{2} + x - 1 = 0\\\frac{-b+-\sqrt{b^{2}-4ac } }{2a} \\\frac{-1+-\sqrt{1^{2}-4*6*(-1) } }{2*6}\\\frac{-1+-\sqrt{1+24} }{12}\\\frac{-1+-\sqrt{25} }{12}\\\frac{-1+-5 }{12}\\x1 = (-1+5) / 12 = \frac{4}{12} = \frac{1}{3} \\x2 = (-1-5) / 12 = -\frac{6}{12} = -\frac{1}{2}$

b)

$3x^{2} -7x +2 = 0\\\frac{-b+-\sqrt{b^{2}-4ac } }{2a} \\\frac{-(-7)+-\sqrt{(-7)^{2}-4*3*2 } }{2*3}\\\frac{7+-\sqrt{49-24} }{6}\\\frac{7+-\sqrt{25 } }{6}\\\frac{7+-5 }{6}\\x1 = (7+5) / 6 = 12 / 6 = 2\\x2 = (7-5) / 6 = \frac{2}{6} = \frac{1}{3}$