Question

Encontre as medidas de h e b no triangulo abaixo

Answer 1

(b.h)/2=16.x=8x
               2
$Hip^{2}$=$Cat^{2}$+$Cat^{2}$
$16^{2}$=$8^{2}$+$x^{2}$
256=64+$x^{2}$
192=$x^{2}$
$\sqrt{192}$=x
13,85=x