Question

encontre a raiz da ecuaçao x2-5x+6=0​

Answer 1

x²-5x+6=0

$\Delta = {b}^{2} - 4.a.c \\ \Delta = {( - 5)}^{2} - 4.1.6 \\ \Delta = 25 - 24 \\ \Delta = 1$

$x = \frac{ -b ± \sqrt{\Delta} }{2a} \\ x = \frac{ - ( - 5) ± \sqrt{1}}{2.1}$

$x = \frac{5 ±1 }{2}$

$x' = \frac{5 + 1}{2} = \frac{6}{2} = 3 \\ x'' = \frac{5 - 1}{2} = \frac{4}{2} = 2$

s={2,3}

Answer 2

x2-5x+6=0

a = 1 b = -5 c = 6

∆ = (-5)² - 4.1.6

∆ = 25 - 24

∆ = 1

x = -(-5) ± √1/2.a

x = 5 ± 1/2

x¹ = 5+1/2 = 3

x² = 5-1/2 = 2

S = (2,3)