Question

Encontre a medida de cada ângulo demarcado​

Answer 1

Explicação passo-a-passo:

$a)\\ tg\alpha ={50\over50}\\ \\ tg\alpha =1\\ \\ \alpha =45^{\circ}\\ \\ b)\\ \\ tg\alpha ={8\sqrt{3} \over3}\div8\\ \\ tg\alpha ={8\sqrt{3} \over3}\times{1\over8}\\ \\ tg\alpha ={\sqrt{3} \over3}\\ \\ \alpha =30^{\circ}\\ \\ c)\\ cos\alpha ={2\sqrt{5} \over4\sqrt{5} }\\ \\ cos\alpha ={1\over2}\\ \\ \alpha =60^{\circ}$