Question

encontre a matriz A=(aij)4×3 tal que aij=3.(i+j)-2i

obs:Só responde quem souber!​​

Answer 1

$\boxed{\begin{array}{l}\sf a_{ij}=3\cdot(i+j)-2i\\\sf a_{ij}=3i+3j-2i\\\sf a_{ij}=i+3j\\\sf a_{11}=1+3\cdot1=4\\\sf a_{12}=1+3\cdot2=7\\\sf a_{13}=1+3\cdot3=10\\\sf a_{21}=2+3\cdot1=5\\\sf a_{22}=2+3\cdot2=8\\\sf a_{23}=2+3\cdot3=11\\\sf a_{31}=3+3\cdot1=6\\\sf a_{32}=3+3\cdot2=9\\\sf a_{33}=3+3\cdot3=12\\\sf a_{41}=4+3\cdot1=7\\\sf a_{42}=4+3\cdot2=10\\\sf a_{43}=4+3\cdot3=13\end{array}}$

$\Large\boxed{\begin{array}{l}\sf A=\begin{bmatrix}\sf4&\sf7&\sf10\\\sf5&\sf8&\sf11\\\sf6&\sf9&\sf12\\\sf7&\sf10&\sf13\end{bmatrix}\end{array}}$