Question

encontre a incógnita x
$B)\frac{4x-2}{3} = \frac{5(x+3}{2} \\\\\\C)3(x-4)+8=5\\\\\\D)\frac{2x-3}{4} + \frac{x-1}{2} = \frac{5-x}{2}$

Answer 1

a) Aplique a distributiva:

$\frac{4x-2}{3}  = \frac{5x+15}{2}$

Depois multiplica cruzado:

2.(4x-2) = 3(5x+15)

8x-4=15x+45

-15x+8x-4=45

-15x+8x = 45+4

-7x = 49

x = -7

b) Aplique a distributiva:

3x-12+8=5

3x - 4 = 5

3x = 5+4

x=9/3

x=3

c) Multiplique x-1/2 por 2/2 para termos o denominador em comum

$\frac{2x-3}{4} +  \frac{x-1}{2}* \frac{2}{2} = \frac{5-x}{2}$

$\frac{2x-3}{4} +  \frac{(x-1)*2}{2*2} = \frac{5-x}{2}$

$\frac{2x-3}{4} +  \frac{(x-1)*2}{4} = \frac{5-x}{2}$

$\frac{2x-3 + (x-1)*2}{4}  = \frac{5-x}{2}$

Multiplique 5-x/2 por 2/2

$\frac{4x-5}{4}  = \frac{5-x}{2} * \frac{2}{2}$

$\frac{4x-5}{4}  = \frac{10-2x}{4}$

Denominadores iguais, igualamos os numeradores:

4x - 5 = 10 - 2x

4x + 2x - 5 = 10

6x = 10 + 5

x= 15/6 -> simplificando por 3

x=5/2