Question

encontre a geratriz de cada dízima
a)0,222...
b)0,121212
c)1,121212​

Answer 1

$\frac{2}{9}$




$\frac{12}{99}$




$\frac{111}{99}$

Answer 2

Oi...

a) 0,222... = 2/9

b) 0,121212... = 12/99 ÷ 3 = 4/33

c) 1,121212... = 1 + 12/99 = 111/99 ÷3 = 37/33

Bons estudos