Question

Encontre a derivada de f(x) = x ln x + tgx

Answer 1

f(x) = x lnx + tgx

f'(x) = x.(lnx)' + lnx.x' +(tgx)'

f'(x) = x.1/x +lnx . 1 + sec²x

f'(x) = 1 + lnx + sec²x