Question

Encontre a derivada.

Answer 1

$f'(x)=e^{3x^2+1} \\ \\ f'(x)=e^{3x^2+1}.[(3x^2+1)\ln(e)]' \\ \\ f'(x)=e^{3x^2+1}.(3x^2+1)'\ln(e)+(3x^2+1)\ln(e)' \\ \\ f'(x)=e^{3x^2+1}.(6x+0)\ln(e)+(3x^2+1).0 \\ \\ f'(x)=e^{3x^2+1}.6x\ln(e) \\ \\ f'(x)=e^{3x^2+1}.6x.1 \\ \\ f'(x)=e^{3x^2+1}.6x \\ \\ f'(x)=6e^{3x^2+1}x$