Question

em que pontos a parábola corresponde a f(x) = x² -3x +2 cruza os eixos x e y?

Answer 1

corta o eixo x nas raízes

f(x)=x²-3x+2

x²-3x+2=0

Δ=b²-4ac
Δ=(-3)²-4(1)(2)
Δ=9-8
Δ=1

x=$x= \frac{-b\pm \sqrt{\Delta} }{2a} = \frac{3\pm1}{2} \\ \\ x'= \frac{3+1}{2} = \frac{4}{2} =2 \\ \\ x"= \frac{3-1}{2} = \frac{2}{2} =1 \\ \\ \\ corta~~eixo~~x~~nos~~pontos \\ \\ (2,0)~e~(1,0)$

$y=c=2 \\ \\ corta~~eixo~~y~~no~~ponto \\ \\ (0,2)$