Question

em complexos - calcule a) i126+i31-i180 b) i36+i102-i50 c)i356+i73+i14

Answer 1

a)

$<var>i^1^2^6+i^3^1-i^1^8^0</var>$

-1-i-1=-2-i

b)

$<var>i^3^6+i^1^0^2-i^5^0</var>$

1-1+1=1

c)

$<var>i^3^5^6+i^7^3+i^1^4</var>$

1+i-1=i

   

Answer 2

a)

$<var>i^{126}+i^{31}-i^{180}=-1+(-i)-1=-2-i</var>$

b)

$<var> i^{36}+i^{102}-i^{50}=1+(-1)-(-1)=1</var>$

 

$<var>i^{356}+i^{73}+i^{14}=1+i+(-1)=i</var>$