Question

×Elevado a 2 + 6x + 8 = 0

Answer 1

Boa noite!!! Vamos lá resolver:)


$x {}^{2} + 6x + 8 = 0 \\ x {}^{2} + 4x + 2x + 8 = 0 \\ x \times (x + 4) + 2(x + 4) = 0 \\ (x + 4) \times (x + 2) = 0 \\ x + 4 = 0 \\ x + 2 = 0 \\ x = - 4 \\ x = - 2$

Resposta final: -4 e -2



Espero ter lhe ajudado:) Bons estudos:)

Answer 2

x² + 6x + 8 = 0

a = 1
b = 6
c = 8

Δ = b² -4 .a . c
Δ = 6² -4 . 1 . 8
Δ = 36 - 32 
Δ = 4

$\mathtt{ \dfrac{-b+-~\sqrt{\Delta}}{2~.~a}~~=~~\dfrac{-6+-~\sqrt{4}}{2~.~1}~~=~~\dfrac{-6+-~2}{2}} \\ \\ \\ \mathtt{x' = ~~\dfrac{-6+2}{2}~~=~~-\dfrac{4}{2}~~=~~-2} \\ \\ \\ \mathtt{x'' =~~\dfrac{-6-2}{2}~~=~~~-\dfrac{8}{2}~~=~~-4}$

Resposta: S{-2 e -4}