Question

Efetuem:

a) i^9
b) i^14
c) i^60
d) i^99
e) i^1035
f) (-i)^16

Answer 1

sabendo que i^2 = -1, i^par=-1, temos

a) i^9 = i^8 x i^1 = -1x i = - i
b) i^14 = -1
c) i^60 = -1
c) i^99 = i^98 x i^1 = -1 x i = -i
d) i^1035 = i^1034 x i^1 = -1 x i = -i
e)(-i)^16 = (-1)^16 x i^16 = -1 x -1 = 1