Question

Efetue =
-x²+6x-5=0
Me ajudem

Answer 1

$Δ = {6}^{2} - 4.( - 1).( - 5) \\ Δ = 36 - 4.( - 1).( - 5) \\ Δ = 36 - 20 \\ Δ = 16$

$\frac{ {36} + 4 }{2} = 20$

$\frac{36 - 4}{2} = 16$

Resposta:

S = {20, 16}

Answer 2

Δ=6

2

−4.(−1).(−5)

Δ=36−4.(−1).(−5)

Δ=36−20

Δ=16

\frac{ {36} + 4 }{2} = 20

2

36+4

=20

\frac{36 - 4}{2} = 16

2

36−4

=16

Resposta:

S = {20, 16}