Matemática, perguntado por cauan32285, 8 meses atrás

efetue os cálculos algébricos a seguir​

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Respondido por CyberKirito
0

\Large\boxed{\begin{array}{l}\sf\dfrac{5}{2}+\dfrac{3}{4}=\dfrac{10+3}{4}=\dfrac{13}{4}\\\\\sf\dfrac{3}{2}+\dfrac{7}{3}=\dfrac{9+14}{6}=\dfrac{23}{6}\\\\\sf\dfrac{4}{3}-\dfrac{1}{6}=\dfrac{8-1}{6}=\dfrac{7}{6}\\\\\sf\dfrac{7}{4}-\dfrac{8}{9}=\dfrac{63-32}{36}=\dfrac{31}{36}\end{array}}

\large\boxed{\begin{array}{l}\underline{\rm Vers\tilde ao\,para\,web:}\\\sf\bigg(+\dfrac{\backslash\!\!\!2^1}{3}\bigg)\cdot\bigg(-\dfrac{1}{\backslash\!\!\!4_2}\bigg)=-\dfrac{1}{6}\\\\\sf\bigg(-\dfrac{\backslash\!\!\!5^1}{\backslash\!\!\!3_1}\bigg)\cdot\bigg(+\dfrac{\backslash\!\!\!6^2}{\backslash\!\!\!5_1}\bigg)=-\dfrac{2}{1}=-2\\\\\sf\bigg(+\dfrac{2}{5}\bigg)\div\bigg(-\dfrac{3}{4}\bigg)=\bigg(+\dfrac{2}{5}\bigg)\cdot\bigg(-\dfrac{4}{3}\bigg)=-\dfrac{8}{15}\end{array}}

\large\boxed{\begin{array}{l}\underline{\rm Vers\tilde ao\,para\,app:}\\\sf\bigg(+\dfrac{\cancel{2}^1}{3}\bigg)\cdot\bigg(-\dfrac{1}{\cancel{4}_2}\bigg)=-\dfrac{1}{6}\\\\\sf\bigg(-\dfrac{\cancel{5}^1}{\cancel{3}_1}\bigg)\cdot\bigg(+\dfrac{\cancel{6}^2}{\cancel{5}_1}\bigg)=-\dfrac{2}{1}=-2\\\\\sf\bigg(+\dfrac{2}{5}\bigg)\div\bigg(-\dfrac{3}{4}\bigg)=\bigg(+\dfrac{2}{5}\bigg)\cdot\bigg(-\dfrac{4}{3}\bigg)=-\dfrac{8}{15}\end{array}}

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