Question

efetue o quadrado da soma e da diferença:
a) (x+4y)²
b) (3a+1/2)²
c) (6-n)²
d) (x-y)²
URGENTE​

Answer 1

$\red{a)(x + 4y) {}^{2} } \\ \red{(x + 4y) {}^{2}} \\ \red{x {}^{2} + 2x \times 4y + (4y) {}^{2}} \\ \red{2x \times 4y } \\ \red{8xy} \\ \red{x {}^{2} + 2x \times 4y(4y) {}^{2}} \\ \red{x {}^{2} + 8xy + (4y) {}^{2}} \\ \red{x {}^{2} + 2x \times 4y + (4y) {}^{2}} \\ \red{(4y {}^{2})} \\ \red{4 {}^{2}y {}^{2}} \\ \red{16y {}^{2}} \\ \red{x {}^{2} + 2x \times 4y + (4y) {}^{2}} \\ \red{x {}^{2} + 8xy + 16y {}^{2}} \\ \blue{resposta} \\ \red{x {}^{2} + 8xy + 16y {}^{2}}$

Aplicação Passo a Passo

$\red{b)(3a + \frac{1}{2}) {}^{2}} \\ \red{(3a + \frac{1}{2}) {}^{2}} \\ \red{(3a) {}^{2} + 2 \times 3a \times \frac{1}{2} + ( \frac{1}{2}) {}^{2}} \\ \red{3a ) {}^{2}} \\ \red{3 {}^{2}a {}^{2}} \\ \red {9a {}^{2} } \\ \red{(3a) {}^{2} + 2 \times 3a \times \frac{1}{2} + ( \frac{1}{2}) {}^{2}} \\ \red{9a {}^{2} + 2 \times 3a \times \frac{1}{2} + ( \frac{1}{2}){}^{2} }$

explicação passo a passo

$\orange{continuacao \: da \: b} \\ \red{ (3a) {}^{2} + 2 \times 3a \times \frac{1}{2} + ( \frac{1}{2}) {}^{2}} \\ \red{2 \times 3a \times \frac{1}{2}} \\ \red{3a} \\ \red{(3a) {}^{2} + 2 \times 3a \times \frac{1}{2} + ( \frac{1}{2} {}^{2}} \\ \red{9a {}^{2} + 3a + ( \frac{1}{2}){}^{2} } \\ \red{(3a) {}^{2} + 2 \times 3a \times \frac{1}{2} + ( \frac{1}{2}) {}^{2}} \\ \red{( \frac{1}{2}) {}^{2}} \\ \\ \red{ \frac{1 {}^{2} }{2 {}^{2}}} \\ \\ \red{ \frac{1}{2 {}^{2}}} \\ \\ \red{ \frac{1 {}^{2} }{2 {}^{2} } } \\ \\ \red{ \frac{1}{4}} \\ \red{(3a) {}^{2} + 2 \times 3a \times \frac{1}{2} + ( \frac{1}{2}) {}^{2}}\\ \red{9a {}^{2} + 3a + \frac{1}{4}} \\ \green{resposta} \\ \pink{9a {}^{2} + 3a + \frac{1}{2} }$

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$\red{c)(6 - n) {}^{2}} \\ \red{(6 - n) {}^{2}} \\ \red{6 {}^{2} - 2 \times 6n + n {}^{2}} \\\red{36 - 2 \times 6n + n {}^{2}} \\\red{6 {}^{2} - 2 \times 6n + n {}^{2} } \\ \red{36 - 12n + n {}^{2} } \\ \red{(6 - n) {}^{2} } \\ \red{36 - 12n + n {}^{2} } \\ \red{n {}^{2} - 12n + 36} \\ \green{resposta} \\ \pink{n {}^{2} + 12n + 36 }$

$\red{d)(x - y) {}^{2} } \\ \red{(x - y) {}^{2}} \\ \red{x {}^{2} - 2xy + y {}^{2}} \\ \green{resposta} \\ \pink{x {^{2} - 2xy + y {}^{2}}} \\ \purple{espero \: ter \: te \: ajudado}$

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