Question

efetue desenvolvendo e reduzindo
(x-5)²-10x

(5x-2)² + 3x-1

(x+1)² - (x-1)²

(x+3)² + (x-3)²

(7x+5)² - (7x-5)²

(3x-1) . (3x+1)

Answer 1

(x-5)²-10x = x²-10x+25-10x = x² - 20x + 25

(5x-2)² + 3x-1 = 25x² -20x +4 + 3x - 1 = 25x² -17x +3

(x+1)² - (x-1)² = x² + 2x + 1 -(x² -2x+1) = 4x

(x+3)² + (x-3)² = x²+6x+9+x²-6x+9 = 2x²+18

(7x+5)² - (7x-5)² = 49x² + 70x +25 -(49x² - 70x + 25) = 140x

(3x-1) . (3x+1) = 9x²+ 3x -3x - 1 = 9x² - 1