Question

Efetue as seguintes adições de polinômios: a) (y²+3y-5)+(-3y+7-5y²) = b) (x²-5x+3)+(-4x²-2x) = c) (9x²-4x-3)+(3x²-10) =​

Answer 1

Explicação passo-a-passo:

a) (y²+3y-5)+(-3y+7-5y²)

$- {4y}^{2} + 2 = 0$

${y}^{2} = \frac{ - 2}{ - 4}$

${y}^{2} = \frac{1}{2}$

$y = \sqrt{ \frac{1}{2} }$

$y1 = + \sqrt{ \frac{1}{2} }$

$y2 = - \sqrt{ \frac{1}{2} }$

b) (x²-5x+3)+(-4x²-2x)

$- 3 {x}^{2} - 7x + 3 = 0$

$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a}$

$x = \frac{7 + - \sqrt{( { - 7)}^{2} - 4 \times ( - 3) \times 3 } }{2 \times ( - 3)}$

$x = \frac{7 + - \sqrt{49 + 36} }{ - 6}$

$x = \frac{7 + - \sqrt{85} }{ - 6}$

$x1 = \frac{ - (7 + \sqrt{85)} }{ 6}$

$x2 = \frac{ - (7 - \sqrt{85} )}{6}$

c) (9x²-4x-3)+(3x²-10)

$12 {x}^{2} - 4x - 13 = 0$

$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a}$

$x = \frac{4 + - \sqrt{ {( - 4)}^{2} - 4 \times 12 \times ( - 13)} }{2 \times 12}$

$x = \frac{4 + - \sqrt{16 + 624} }{24}$

$x = \frac{4 + - \sqrt{640} }{24}$

$x = \frac{4 + - 8 \sqrt{10} }{24}$

$x = \frac{1 + - 2 \sqrt{10} }{6}$

$x1 = \frac{1 + 2 \sqrt{10} }{6}$

$x2 = \frac{1 - 2 \sqrt{10} }{6}$