Matemática, perguntado por laramayuminakamura, 10 meses atrás

Efetue as operações e apresente a resposta na forma irredutível:

a) 3/8+1/8

b) 7/10+3/10

c)5/12+9/12

d)10/3+5/3

e)1/2+1/7+1/14

f)2/5+1/4

g)1/8+1/4

h)1/2-3/10

i)3/4-3/16

j)2-5/10

Soluções para a tarefa

Respondido por valterbl
142

Oi

a) 3/8 + 1/8 = 4/8÷4=1/2

b) 7/10+3/10=10/10÷10=1

c) 5/12+9/12 = 14/12÷2=7/6

d) 10/3+5/3 =15/3 ÷3=5

e) 1/2+1/7+1/14=mmc=14

7+2+1/14 = 10/4÷2=5/7

f) 2/5+1/4 =mmc=20

8+5/20=13/20

g) 1/8+1/4=mmc=8

1+2/8 = 3/8

h) 1/2-3/10=mmc=10

5-3/10=2/10÷2=1/5

i) 3/4-3/16=mmc=16

12-3=9/16

j) 2 - 5/10=mmc=2

4-1/2= 3/2

Bons estudos

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