Matemática, perguntado por amandagabriellyff, 6 meses atrás

Efetue as operações de subtração e adição das frações a seguir:
p)
 \frac{6}{7}  -  \frac{1}{3}  +  \frac{4}{3}  =
v)
 \frac{2}{3}  +  \frac{3}{4}  +  \frac{2}{6}  =
w)
 \frac{5}{4}  +  \frac{2}{6}  +  \frac{4}{5}  =
x)
 \frac{10}{3}  +  \frac{1}{5}  -  \frac{2}{3} =
y)
 \frac{7}{5}  +  \frac{2}{3}  -  \frac{1}{3}  =
z)
 \frac{18}{7}  +  \frac{1}{3}  -  \frac{3}{5}  =
a1)
 \frac{3}{4}  +  \frac{4}{5}  -  \frac{3}{10}  =
por favor me ajude !!!​

Soluções para a tarefa

Respondido por SorraBoluaP
1

Resposta:

Explicação passo a passo:

p)

'6/7-1/3+4/3'

"=6/7+3/3''

'=6/7+1'

'=6/7+7/7''

= "13/7"

___________

v)

"2/3+3/4+2/6(:2)/(:2)"

'=2/3+3/4+1/3'

='3/3+3/4'

= '1+3/4'

= (4+3)/4"

= "7/4"

______________

w)

'5/4+2/6+4/5'

'= 5/4+1/3+4/5''

'= (15.5+20+12.4)/60'

''=(75+20+48)/60'

" = (95+48)/60'

'= 143/60'

'4,3,5:2'

'2,3,5:2''

'1,3,5:3'

''1,1,5:5'

"1,1,1'

= 2.2.3.5

= 4.15

= 60

________________

x)'10/3 +1/5 - 2/3'

'=8/3+1/5'

'= (5.8+3)/15'

'= (40+3)/5'

='43/15'

_______________

y)

'7/5+2/3-1/3''

'= 7/5+1/3'

''= (3.7+5)/15'

'= (21+5)/15'

"= 26/15"

____________

z)

'18/7 + 1/3 - 3/5'

'mmc = 105'

'= (15.18+35-21.3)/105'

'= (270+35-63)/1025'

'=(305-63)/105'

= '242/105'

A1)

'3/4+4/5 -3/10'

'=(5.3+4.4-2.3)/20'

'=(15 + 16 - 6)/20'

'= 25/20'

' =5/4'

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