Question

efetue as multiplicacao a) (+2).(+7).(+10)= b) (-4).0.(+3).(-8)= c) (-1).(+2).(-2).(+5).(-3)= d) (+5).(-3).(+2).(+1).(-2)= e) (-2).(-5).(-1).(-3)= f) (-10).(-2).(-10).(-2)= me ajudem por favor

Answer 1

Resposta:

a) (+2).(+7).(+10)

$2 \times 7 \times 10 \\ 14 \times 10 \\ = 140$

b) (-4).0.(+3).(-8)

$- 4 \times 3 \times ( - 8) \\ - 12 \times ( - 8) \\ = 96$

c) (-1).(+2).(-2).(+5).(-3)

$- 1 \times 2 \times ( - 2) \times 5 \times ( - 3) \\ - 2 \times ( - 2) \times ( - 15) \\ 4 \times ( - 15) \\ = - 60$

d) (+5).(-3).(+2).(+1).(-2)

$5 \times ( - 3) \times 2 \times 1 \times ( - 2) \\ - 15 \times 2 \times ( - 2) \\ - 30 \times ( - 2) \\ = 60$

e) (-2).(-5).(-1).(-3)

$- 2 \times ( - 5) \times ( - 1) \times ( - 3) \\ 10 \times ( - 1) \times ( - 3) \\ - 10 \times ( - 3) \\ = 30$

f) (-10).(-2).(-10).(-2)

$- 10 \times ( - 2) \times ( - 10) \times ( - 2) \\ 20 \times 20 \\ = 400$