Question

efetue

A) x²-64=0
a=1 b=0 c=-64

Δ= b -4.a.c

B) 4x²-4x+1= 0

a= 4 b= -4 c= 1

Δ= b -4.a.c

Answer 1

Explicação passo-a-passo:

A)

x² -64=0

a=1

b=0

c=-64

Δ=b²-4ac

Δ=0²-4(1)(-64)

Δ=0+256

Δ=256

$x={-b\pm\sqrt{\Delta} \over2a}={0\pm\sqrt{256} \over2(1)}=\pm{16\over2}=\pm8\\ \\ S=\{-8,+8\}$

B)

4x²-4x+1=0

a=4

b=-4

c=1

Δ=b²-4ac

Δ=(-4)²-4(4)(1)

Δ=16-16

Δ=0

$x={-b\pm\sqrt{\Delta} \over2a}={-(-4)\pm\sqrt{0} \over2(4)}={4\pm0\over8}={1\over2}\\ \\ x'=x"={1\over2}\\ \\ S=\{{1\over2}\}$