Question

efetue:a)(t-6)2= b)(x+1/2)(x-1/2)= c)(y-4)(y+4)=

Answer 1

A) X.(X - 1/2) = 0

Efetuando:

X^2 - 1/2X =

2X^2 - 1X= 0

X(2X - 1)

 X1 = 0

 2X - 1 = 0

 2X = 1

 X2 = 1/2

 

B) (X + 1/2).(X - 1/3) = 0

    X^2 - 1/3X + 1/2X - 1/6 =0

            -1/3 + 1/2 = 1/6(-2 + 3) = 1/6

   X^2 + 1/6X - 1/6 = 0

   6X^2 + X - 1 = 0

Resolvendo por Báskara:

  delta = b^2 - 4.a.c = 1 - 4.6(-1) = 1 + 24 = 25

  raiz delta = = - 5

 

X = (-b +- raiz delta) / 2a

 

X = (-1 + 5) / 2.6

  = 4 / 12

  = 1 / 3

X1 = 1/3

 

X = (- 1 - 5) / 12

  = - 6 / 12

 = - 1/2

X2 = - 1/2

 

C)(X + 2/3).(X - 1/4) = 0

   x^2 - 1/4X + 2/3X - 2/12 = 0

            - 1/4 + 2/3 = 1/12(- 3 + 8) = 5/12

  X^2 + 5/12X - 5/12 = 0

  12X^2 + 5X - 5 = 0

     delta = 25 - 4(12)(-5) = 25 + 240 = 265

     raiz delta = +- raiz de 65

 

X1 = (- 5 + raiz de 65)/24

X2 = (- 5 - raiz de 65)/24

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