Física, perguntado por milenesoares336, 9 meses atrás

Efetue: a)9.10^5 + 4,5.10^7 b)4,5.10^3 + 8,10^3 c)4,2.10^4 - 2,7.10^2 d)1,5.10^2 + 4,3.10^3 e)3,5.10^-5 + 1,2.10^-4 f)3,2.10^3 . 4,5.10^-5 g)5,1.10^32 . 3,2.10^-25 h)9,9.10^3/ 3,3.10^-2 i) 4.10^14 : 2.10^-22

Soluções para a tarefa

Respondido por Usuário anônimo
1

Resposta:

Explicação:

a)

= 9.10^5 + 4,5.10^7

= 0,09.10^2.10^5 + 4,5.10^7

= 0,09 . 10^(2+5) + 4,5.10^7

= 0,09.10^7 + 4,50.10^7

= 4,59.10^7

---------------------

b)

= 4,5.10^3 + 8.10^3

= 4,5 . 10^3 + 8,0 . 10^3

= 12,5 . 10^3

= 1,25.10.10^3

= 1,25 . 10^(1+3)

= 1,25.10^4

-------------

c)

= 4,2.10^4 - 2,7.10^2

= 420 . 10^(-2).10^4 - 2,7.10^2

= 420,0 .10^2 - 2,7.10^2

= 417,3 . 10^2

= 4,173. 10^(-2).10^2

= 4,173 . 10^(2-2)

= 4,173.10^0

= 4,173 . 1

= 4,173

-----------

d)

= 1,5.10^2 + 4,3.10^3

= 0,15.10.10^2 + 4,30 .10^3

= 0,15 . 10^3 + 4,30 . 10^3

= 4,45.10^3

--------------

e)

= 3,5.10^-5 + 1,2.10^-4

= 0,35.10.10^(-5) + 1,2 . 10^(-4)

= 0,35.10^(-4) + 1,20 . 10^(-4)

= 1,55.10^(-4)

----------------------

f)

= 3,2.10^3 . 4,5.10^-5

= 32.10^(-1).10^3 . 45.10^(-1).10^(-5)

= 32.10^2 . 45 . 10^(-6)

= 4.8.9.5 . 10^(2-6)

= 4.9.8.5. 10^(-4)

= 36.40.10^(-4)

= 36.4.10^1.10^(-4)

= 144.10^1.10^(-4)

= 1,44.10^2.10^(1-4)

= 1,44.10^2. 10^(-3)

= 1,44 . 10^(2-3)

= 1,44 . 10^(-1)

---------------

g)

= 5,1.10^32 . 3,2.10^-25

= 51.10^(-1).10^32 . 32 . 10^(-1).10^(-25)

= 51.10^(-1+32) . 32 . 10^(-1-25)

= 51.32 . 10^31 . 10^(-26)

= 51.32 . 10^(31-26)

= 5,1. 10 . 32 . 10^5

= 32. 5,1 . 10.10^5

= 32 . 5,1 . 10^(1+5)

= 163,2 . 10^6

= 1,632 . 10^2 . 10^6

= 1,632. 10^(2+6)

= 1,632.10^8

--------------

h)

= 9,9.10^3/ 3,3.10^-2

= 9,9/3,3 . 10^3/ 10^(-2)

= 3 . 10^(3). 10^(2)

= 3.10^(3+2)

= 3. 10^5

-----------------------

i)

= 4.10^14 : 2.10^-22

= 2 . 10^[(14)-(-22)]

= 2 . 10^(14+22)

= 2. 10^36

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