Question

Efetue :

a) 3$\sqrt{5}$ + $\sqrt{5}$ - 6$\sqrt{5}$ =

b) 5$\sqrt[5]{3}$ + 2$\sqrt[5]{3}$ - 2$\sqrt[5]{3}$ + $\sqrt[5]{3}$ =

c) - 4 + $\sqrt[3]{5}$ + 2$\sqrt[3]{5}$ - 4 =

d) 2$\sqrt[5]{3}$ - 2$\sqrt{3}$ + 3$\sqrt{3}$ + 3$\sqrt[5]{3}$ =

e) $\sqrt{50}$ + $\sqrt{18}$ - $\sqrt{8}$ =

f) 2$\sqrt{27}$ - 5$\sqrt{12}$ =

g) 4$\sqrt{63}$ - $\sqrt{7}$ =

h) $\sqrt{12}$ + $\sqrt{75}$ + $\sqrt{108}$ =

Answer 1

Resposta:

$a) -2\sqrt{5}\\ b) 6\sqrt[5]{3} \\c)-8+3\sqrt[3]{5}\\ d) \sqrt{3}+5\sqrt[5]{3}\\ e)5\sqrt{2}+3\sqrt{2}-2\sqrt{2} = 6\sqrt{2}\\ f)6\sqrt{3} -10\sqrt{3}= -4\sqrt{3} \\ g)12\sqrt{7}-\sqrt{7}=11\sqrt{7}\\ h)2\sqrt{3}+5\sqrt{3} +6\sqrt{3} =14\sqrt{3}$

Explicação passo-a-passo:

Answer 2

Resposta:

\sqrt[5]{ $a^{3}}$

Explicação passo-a-passo: