Question

Efetue:
A) (1+i)^100;
B) (1-i)^100;
C) (1-i)^101.

Answer 1

$A) \ (1+i)^{100}=[(1+i)^4]^{25}=(-4)^{25}\\ B) \ (1+i)^{100}=[(1-i)^4]^{25}=(-4)^{25}\\ C) \ (1-i)^{101}=(1-i)^{100}*(1-i)=(-4)^{25}(1-i)$