Question

Efetue: √2+√8+√32+√128

Answer 1

$\sqrt{8} = \sqrt{2*4}= \sqrt{2} \sqrt{4} = \sqrt{2}\sqrt{2^2} =2 \sqrt{2} \sqrt{32} = \sqrt{2*16}= \sqrt{2} \sqrt{16} = \sqrt{2}\sqrt{4^2} =4 \sqrt{2} \sqrt{128} = \sqrt{2*64}= \sqrt{2} \sqrt{64} = \sqrt{2}\sqrt{8^2} =8\sqrt{2} \sqrt{2}+ \sqrt{8}+ \sqrt{32}+ \sqrt{128}= \sqrt{2}+2 \sqrt{2}+4 \sqrt{2}+8 \sqrt{2}=15 \sqrt{2}$