Question

Efetue (1+i) elevado a 8

Answer 1

$(1+i)^8=\\\\(1+i)^2(1+i)^2(1+i)^2(1+i)^2=\\\\(1+2i+i^2)(1+2i+i^2)(1+2i+i^2)(1+2i+i^2)=\\\\(1+2i-1)(1+2i-1)(1+2i-1)(1+2i-1)=\\\\(2i)(2i)(2i)(2i)=\\\\16i^4=\\\\\boxed{16}$