Question

Efetuando-se a questao abaixo, obtêm-se

Answer 1

$\frac{ \sqrt{3} + 2 \sqrt{2} }{ \sqrt{3} - 2 \sqrt{2} } + \frac{2 \sqrt{2} - \sqrt{3} }{ \sqrt{3} +2 \sqrt{2} } =$

$\frac{ \sqrt{3} + \sqrt{8} }{ \sqrt{3} - \sqrt{8} } + \frac{ \sqrt{8} - \sqrt{3} }{ \sqrt{3} + \sqrt{8} } =$

$\frac{ \sqrt{3} + \sqrt{8} }{ \sqrt{3} - \sqrt{8} } . \frac{( \sqrt{3} + \sqrt{8}) }{( \sqrt{3} + \sqrt{8})} + \frac{ \sqrt{8} - \sqrt{3} }{ \sqrt{3} + \sqrt{8} } . \frac{( \sqrt{3} - \sqrt{8}) }{ (\sqrt{3} - \sqrt{8}) } =$

$\frac{3+2 \sqrt{24}+ 8 }{( \sqrt{3})^2 - (\sqrt{8})^2 } + \frac{3-2 \sqrt{24}+ 8 }{( \sqrt{3})^2 - (\sqrt{8})^2 } =$

$\frac{11+4 \sqrt{6} }{-5} } + \frac{11-4 \sqrt{6} }{-5} =$

$\frac{-11+4 \sqrt{6} - 11 -4 \sqrt{6} }{-5} =$

$\frac{-22}{5}$