Question

Efetuando a divisão x2+xy+5x+5y/x2+2xy+y2 : x2-25/2x-10 obtém-se :
A) 2
B) 1/x+y
C) 2/x+y
D ) 2/(X+Y)2

Com cálculo

Answer 1

$\frac{ x^{2} +xy+5x+5y}{ x^{2} +2xy+y^{2} } : \frac{x^{2}-25 }{2x-10} = \frac{x(x+y)+5 (x+y)}{(x+y)(x+y)} . \frac{2 (x-5)}{(x-5)(x+5)} =\frac{(x+y)(x+5)}{(x+y)(x+y)} . \frac{2}{(x+5)} = \frac{2}{x+y}$