Question

EDO
xy' =raiz(x^2+y^2)

Answer 1

Resposta:

Explicação passo-a-passo:

- r a i zx2+ yx -y2r a i z= 0

( - r a i z) ⋅x2+ ( y) ⋅ x + ( -y2r a i z) =0

x =- ( y) ±( y)2- 4 ⋅ ( - r a i z) ⋅ ( -y2r a i z)-------------------------√2 ⋅ ( - r a i z), - r a i z≠ 0

x =- y±y2- ( 4y2r2uma2eu2z2)---------------√- 2 r a i z

x =y±- 4y2r2uma2eu2z2+y2---------------√2 r a i z

- r a i zx2+ yx -y2r a i z= 0

Radicand menor que zero.