Question

Edivaldo Araújo Suassuna por favor me ajudem ​

Answer 1

$\frac{-b +-\sqrt{b^{2}-4ac} }{2a}$

$\frac{-(-2) +-\sqrt{-2^{2}-4.1.(-8)} }{2.1}$

$\frac{2 +-\sqrt{4-(-32)} }{2}$

$\frac{2 +-\sqrt{36} }{2}$

$\frac{2 +-6 }{2}$

$\frac{2 + 6}{2} = \frac{8}{2} = 4$

$\frac{2 - 6}{2} = \frac{-4}{2} = -2$

Resposta: 4 e -2