Matemática, perguntado por Mily9581, 4 meses atrás

É urgente, me ajudem por favor ​

Anexos:

Soluções para a tarefa

Respondido por correiamartins1leand
0

Resposta:

1) d

2) b

3) c

4) c

5) a

6) erro na alternativa, avise seu professor(a)

Explicação passo a passo:

1)D=\left[\begin{array}{cc}1&0&\\0&1&\\\end{array}\right]=(1+1)-(0+0)=2\\\\\\2)\left[\begin{array}{ccc}5&8&\\14&3&\\\end{array}\right]+\left[\begin{array}{ccc}2&8&\\7&2&\\\end{array}\right]=\left[\begin{array}{ccc}5+2&8+8&\\14+7&3+2&\\\end{array}\right]=\left[\begin{array}{ccc}7&16&\\21&5&\\\end{array}\right]\\\\\\    3)trA=\left[\begin{array}{ccc}2&-1&3\\1&5&0\\6&4&2\end{array}\right]=2+5+2=9\\\\\\

4)D=\left[\begin{array}{ccc}1&1&1\\2&3&5\\4&9&25\end{array}\right]\left\begin{array}{cCc}1&1&\\2&3&\\4&9&\end{array}\right]=\\(1.3.25+1.5.4+1.2.9)-(1.3.4+1.5.9+1.2.25)=(75+20+18)-(12+45+50)=(113)-(107)=6\\\\\\5)D=\left[\begin{array}{cc}2&5&\\1&4&\\\end{array}\right]=(2.4)-(5.1)=8-5=3\\\\\\6)\left[\begin{array}{cc}5&8&\\14&3&\\\end{array}\right]-\left[\begin{array}{cc}2&8&\\7&2&\\\end{array}\right]=\left[\begin{array}{cc}5-2&8-8&\\14-7&3-2&\\\end{array}\right]=

\left[\begin{array}{cc}3&0&\\7&1&\\\end{array}\right]

avisa a sua professora que ela errou nas alternativas da resposta da 6, ela colocou respostas para A+B, sendo que ela pediu A-B

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