Question

É pra amanhã, por favor!​

Answer 1

Resposta:

Explicação passo-a-passo:

$\left[\begin{array}{ccc}1&6&-1\\2&-5&4\end{array}\right] \left[\begin{array}{ccc}2&3&9\\1&0&0\\0&1&8\end{array}\right] =\left[\begin{array}{ccc}(2+6)&(3-1)&(9-8)\\(4-5)&(6+4)&(18+32)\\\end{array}\right] =\left[\begin{array}{ccc}8&2&1\\-1&10&50\end{array}\right]$