Question

é para hj ajuda ai pfvvvv

Answer 1

$\large\bm{ \dfrac{2x}{3} + 5 \left(2x - 3\right) = \dfrac{3\left(4x - 1\right)}{2} + 1} \\\\ \large\bm{ \frac{2x}{3} + 10x - 15 = \dfrac{3\left(4x - 1\right)}{2} + 1 } \\\\ \large\bm{ \dfrac{2x}{3} + 10x - 15 = \dfrac{12x - 3}{2} + 1} \\ \\ \large\bm{4x + 60x - 90 = 3\left(12x - 3\right) + 6} \\\\ \large\bm{64x - 90 = 3\left(12x - 3\right)} + 6 \\\\ \large\bm{64x - 90 = 36x - 9 + 6} \\\\ \large\bm{64x - 90 = 36x - 3} \\ \large\bm{64x - 90 - 36x = - 3} \\ \\ \large\bm{64x - 36x = - 3 + 90} \\ \\ \large\bm{28x = - 3 + 90} \\ \\ \large\bm{28x = 87} \\\\ \large\bm{x = \dfrac{87}{28} } \\\\ \bm{\large\boxed{\boxed{  { \large \bm{ x = \dfrac{87}{28} }}}}}$

${\large\boxed{\boxed{  { \large \bm{ Bons~Estudos} }}}}$