Question

Dividir o número 2640 em partes diretamente proporcionais a 3/4 e 1/2 e inversamente proporcionais a 5/6 e 2/3.

Answer 1

2640=k*(3/4+1/2 +6/5+3/2)

2640=k*(3/4+1/2 +3/2+6/5)

2640=k*(3/4+4/2+6/5)

2640=k*(3/4+8/4+6/5)


2640=k*(11/4+6/5)

2640=k*(55+24)/20

2640 * 20=79k

k=52800/79

52800/79 *3/4

52800/79 *1/2

52800/79 *6/5

52800/79 *3/2