Question

Dividir 6500 em partes inversamente proporcionais aos numeros 2, 3 e 4

Answer 1

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$\frac{x}{ \frac{1}{2} } = \frac{y}{ \frac{1}{3} } = \frac{z}{ \frac{1}{4} } = \\ \\ \frac{x+y+z}{ \frac{1}{2}+ \frac{1}{3} + \frac{1}{4} } = \frac{6500}{ \frac{6+4+3}{12} } = \frac{6500}{ \frac{13}{12} } =\not6500^{500}\times \frac{12}{\not13} =500\times12=6000$
$-------------- \\ \frac{x}{ \frac{1}{2} } =6000~~~~~~~~~~ \frac{y}{ \frac{1}{3} } =6000~~~~~~ ~~~~\frac{z}{ \frac{1}{4} } =6000 \\ \\ x=6000\div2~~~~~~y=6000\div3~~~~~~z=6000\div 4 \\ \\ x=3000~~~~~~~~~~~y=2000~~~~~~~~~~~~z=1500$