Divida o número 600 em partes diretamente proporcionais 12,4,2 e 6 r inversamente proporcionais 6,2,3 e 18
Soluções para a tarefa
Explicação passo-a-passo:
x/12 = y/4 = z/2 = t/6 = 600/12+4+2+6+
x/12 = y/4 = z/2 = t/6 = 600/24
x / 12 = 600/24
24x = 12 . 600
24x = 7200
x = 300
y /4 = 600/24
24y = 4 . 600
24y = 2400
y = 100
z / 2 = 600/24
24z = 2 . 600
24z = 1200
z = 50
t / 6 = 600/24
24t = 6 . 600
24t = 3600
t = 150
inversamente
k . 1/6+ k . 1/2+ k . 1/3+ k . 1/18 = 600
k . 3/18+ k . 9/18+ k . 6/18+ k . 1/18 = 600
k . 19/18 = 600
19k = 600 . 18
19k = 10800
k = 10800/19
k = 568,421052631579
6x = 568,421052631579
x = 568,421052631579/6
x = 94,7368421052632
2y = 568,421052631579
y = 568,421052631579/2
y = 284,210526315789
3z = 568,421052631579
z = 568,421052631579/3
z = 189,473684210526
18t = 568,421052631579
t = 568,421052631579/18
t = 31,5789473684211