Divida 215 em partes diretamente proporcionais a 3/4, 5/2 e 1/3
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Boa tarde Artur!
Solução!
![x+y+x=215\\\
\frac{3}{4}+ \frac{5}{2}+ \frac{1}{3}\\\\\
Fazendo~~o~~MMC!\\\\\\
(4,2,3)=12\\\\\\
\dfrac{x}{9} + \dfrac{y}{30} + \dfrac{z}{4} =215](https://tex.z-dn.net/?f=x%2By%2Bx%3D215%5C%5C%5C%0A+%5Cfrac%7B3%7D%7B4%7D%2B+%5Cfrac%7B5%7D%7B2%7D%2B+%5Cfrac%7B1%7D%7B3%7D%5C%5C%5C%5C%5C%0AFazendo%7E%7Eo%7E%7EMMC%21%5C%5C%5C%5C%5C%5C%0A%284%2C2%2C3%29%3D12%5C%5C%5C%5C%5C%5C%0A++%5Cdfrac%7Bx%7D%7B9%7D+%2B+%5Cdfrac%7By%7D%7B30%7D+%2B+%5Cdfrac%7Bz%7D%7B4%7D+%3D215 "x+y+x=215\\\
\frac{3}{4}+ \frac{5}{2}+ \frac{1}{3}\\\\\
Fazendo~~o~~MMC!\\\\\\
(4,2,3)=12\\\\\\
\dfrac{x}{9} + \dfrac{y}{30} + \dfrac{z}{4} =215")
Vamos determinar agora a constante de proporcionalidade.
![\dfrac{x}{9} + \dfrac{y}{30} + \dfrac{z}{4} = \dfrac{215}{43}\\\\\\\
K=\dfrac{215}{43}\\\\\\\
K=5\\\\\\\\
x=5\times9=45\\\\
y=5\times30=150\\\\\
z=5\times4=20](https://tex.z-dn.net/?f=+%5Cdfrac%7Bx%7D%7B9%7D+%2B+%5Cdfrac%7By%7D%7B30%7D+%2B+%5Cdfrac%7Bz%7D%7B4%7D+%3D+%5Cdfrac%7B215%7D%7B43%7D%5C%5C%5C%5C%5C%5C%5C%0AK%3D%5Cdfrac%7B215%7D%7B43%7D%5C%5C%5C%5C%5C%5C%5C%0AK%3D5%5C%5C%5C%5C%5C%5C%5C%5C%0Ax%3D5%5Ctimes9%3D45%5C%5C%5C%5C%0Ay%3D5%5Ctimes30%3D150%5C%5C%5C%5C%5C%0Az%3D5%5Ctimes4%3D20+ "\dfrac{x}{9} + \dfrac{y}{30} + \dfrac{z}{4} = \dfrac{215}{43}\\\\\\\
K=\dfrac{215}{43}\\\\\\\
K=5\\\\\\\\
x=5\times9=45\\\\
y=5\times30=150\\\\\
z=5\times4=20")
Boa tarde!
Bons estudos!
Solução!
Vamos determinar agora a constante de proporcionalidade.
Boa tarde!
Bons estudos!
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