Question

dívida 1459 em partes inversamente proporcionais a 5, 7, 8 e 9​

Answer 1

$\frac{k}{5}+\frac{k}{7}+\frac{k}{8}+\frac{k}{9}=1459\\\\\frac{504k+360k+315k+280k}{2520}=\frac{3676680}{2520}\\\\504k+360k+315k+280k=3676680\\1459k=3676680\\k=3676680/1459\\k=2520$

Como k=2520, cada parte será:

$\frac{k}{5}=\frac{2520}{5}=504\\\\\frac{k}{7}=\frac{2520}{5}=360\\\\\frac{k}{8}=\frac{2520}{5}=315\\\\\frac{k}{9}=\frac{2520}{5}=280$