Question

detrmina as massas moleculares das seguntes subistancias (MA C=12u. h=1u o=16 U N= 14u Ca=40. s=32u b) 3H2 SO4 c) C12H24O12 d)c8H4O5 e)co2 (nh4)2

Answer 1

Resposta:

b)3H2SO4

3(1×2+32+16×4)=

3(2+32+64)=

3(98)=

294 g

c)C12H24O12

12×12+1×24+16×12=

144+24+192=

360g

d)C8H4O5

12×8+1×4+16×5=

96+4+80=

180g

e)CO2(NH4)2

12+16×2+(14+1×4)2=

12+32+(18)2=

12+32+36=

80g