detremine o máximo divisor comum de:
a)(36,48,108)
b)(125,250,625)
c)(248,128)
Soluções para a tarefa
Explicação passo-a-passo:
a)(36,48,108)
36,48,108/2
18,24,54/2
9,12,27/3
3,4,9/3
1,4,3/3
1,4,1/2
1,2,1/2
1,1,1/_____
mdc= 2.2.3=4.3=12
b)(125,250,625)
125,250,625/5
25,50,125/5
5,10,25/5
1,2,5/2
1,1,5/5
1,1,1/____
mdc=5.5.5=125
c)(248,128)
248,128/2
124,64/2
62,32/2
31,16/31
1,16/2
1,8/2
1,4/2
1,2/2
1,1/_____
mdc=2.2.2=8
Espero ter ajudado!
OI...
O MDC de:
a) (36, 48, 108)
36, 48, 108 | 2
18, 24, 54 | 2
9, 12, 27 | 2
9, 6, 27 | 2
9, 3, 27 | 3
3, 1, 9 | 3
1, 1, 3 | 3
1, 1, 1
MDC = 2 . 2 . 3 = 12
MDC = 12
b) (125, 250, 625)
125, 250, 625 | 2
125, 125, 625 | 5
25, 25, 125 | 5
5, 5, 25 | 5
1, 1, 5 | 5
1, 1, 1
MDC = 5 . 5 . 5 = 125
MDC = 125
c) (248, 128)
248, 128 | 2
124, 64 | 2
62, 32 | 2
31, 16 | 2
31, 8 | 2
31, 4 | 2
31, 2 | 2
31, 1 | 31
1, 1
MDC = 2 . 2 . 2 = 8
MDC = 8
Espero ter ajudado.