Question

detreminar o 14* termo da PG (1536,768,384,192,...)

Answer 1

q = a₂ / a₁
q = 768 / 1 536
q = 1/2

a₁₄ = a₁ * q¹³
a₁₄ = 1 536 * (1/2)¹³
a₁₄ = 1 536 * 1/8 192
a₁₄ = 1 536 / 8 192
a₁₄ = 3/16

Answer 2

(1536, 768, 384, 192, ...)

a₁ = 1536

q = 768/1536 ----- q = 1/2


an = a₁ . q ⁿ ⁻ ¹ -----a₁₄ = 1536 . (1/2) ¹⁴ ⁻ ¹ ----- a₁₄ = 1536 . (1/2)¹³

a₁₄ = 1536 . 1/8192 ---- a₁₄ = 1536/8192 ----- a₁₄ = 3/16