Question

determinr o valor de x no determinante
| × 5 0|
|3 2 -1 | =17
|× 1 1 |
alguém sabe ?

Answer 1

x 5 0 x 5
3 2 -1 3 2
x 1 1 x 1

x. 2 . 1 + 5 . (-1) . x + 0 . 3 . 1 - (0 . 2 . x + x . (-1) . 1 + 5 . 3 . 1) = 17
2x - 5x + 0 - 0 + x - 15 = 17
-2x -15=17
-2x = 17 +15
-2x = 32
x= 32/-2
x = -16