Question

determineo valor real de x para que se tenha rais de x+rais de x-1=rais de 2x-3

Answer 1

\/x + \/(x-1) = \/(2x-3)
[\/x + \/(x-1)]² = [\/(2x-3)]²
x + 2\/x\/(x-1) + x-1 = 2x-3
x + 2\/x(x-1) + x - 1 = 2x - 3
2\/(x²-x) = 2x-3-x-x
2\/(x²-x) = -3
[2\/(x²-x)]² = (-3)²
4(x²-x) = 9
4x²-4x-9 = 0
/\ = (-4)² - 4.4.(-9)
/\ = 16 + 144
/\ = 160
x = (-(-4)+/- \/160)/2.4
160|2
080|2
040|2
020|2
010|2
005|5
001 --> \/160 = 4\/10
x = (4+/-2\/10)/8
x' = (4+2\/10)/8 = (2+\/10)/4
x" = (4-2\/10)/8 = (2-\/10)/4