Question

determinei o valor de x abaixo

Answer 1

Olá Francisco

1a)

x² = 12² + 5²
x² = 144 + 25 = 169
x = 13

1b)

x² = 10² - 6²
x² = 100 - 36 = 64
x = 8

1c)

x² = 5² - 3²
x² = 25 - 9 = 16
x = 4

2)

x² = 5² - 4²
x² = 25 - 16 = 9
x = 3

sen(α) = 4/5  sen(β) = cos(α) = 3/5
cos(α) = 3/5  cos(β) = sen(α) = 4/5
tg(α) = 4/3     tg(β) = cotg(α) = 3/4 

Answer 2

Teorema de Pitágoras:
$a^{2}+ b^{2}= c^{2}$
a)$12^{2}+ 5^{2}= x^{2} = 144+25= x^{2} = 169= x^{2} x= \sqrt{169}= x=13$
b)$6^{2}+ x^{2} = 10^{2} = 36 + x^{2} =100= x^{2} =100-36= x^{2} =64=x= 8$
c)$3^{2}+ x^{2} = 5^{2} = 9+ x^{2} =25= x^{2} =25-9= x^{2} =16=x=4$