Matemática, perguntado por isabelly580, 1 ano atrás

Determine usando a decomposição simultânea.


A) mmc (6,15,21)=
B) mmc (12,18,50)=
C) mmc (15,21,35)=
D) mmc (26,28,88)=
E) mmc (10,21,77)=
F) mmc (600,90,300)=
G) mmc (180,378,840,1470)=
H) mmc (77,143,247,133)=


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Soluções para a tarefa

Respondido por FioriExatos
50

A) 6, 15, 21 | 2

3, 15, 21 | 3

1, 5, 7 | 5

1, 1, 7 | 7

1, 1, 1 | 1

MMC = 2 . 3 . 5 . 7 = 210

B) 12, 18, 50 | 2

6, 9, 25 | 2

3, 9, 25 | 3

1, 3, 25 | 3

1, 1, 25 | 5

1, 1, 5 | 5

1, 1, 1 | 1

MMC = 2 . 2 . 3 . 3 . 5 . 5 = 900

C) 15, 21, 35 | 3

5, 7, 35 | 5

1, 7, 7 | 7

1, 1, 1 | 1

MMC = 3 . 5 . 7 = 105

D) 26, 28, 88 | 2

13, 14, 44 | 2

13, 7, 22 | 2

13, 7, 11 | 7

13, 1, 11 | 11

13, 1, 1 | 13

1, 1, 1 | 1

MMC = 2 . 2 . 2 . 7 . 11 . 13 = 8008

E) 10, 21, 77 | 2

5, 21, 77 | 3

5, 7, 77 | 5

1, 7, 77 | 7

1, 1, 11 | 11

1, 1, 1 | 1

MMC = 2 . 3 . 5 . 7 . 11 = 2310

F) 600, 90, 300 | 2

300, 45, 150 | 2

150, 45, 75 | 2

75, 45, 75 | 3

25, 15, 25 | 3

25, 5, 25 | 5

5, 1, 5 | 5

1, 1, 1 | 1

MMC = 2 . 2 . 2 . 3 . 3 . 5 . 5 = 1800

G) 180, 378, 840, 1470 | 2

90, 189, 420, 735 | 2

45, 189, 105, 735 | 3

15, 63, 35, 245 | 3

5, 21, 35, 245 | 5

1, 7, 7, 49 | 7

1, 1, 1, 7 | 7

1, 1, 1, 1 | 1

MMC = 2³ . 3³ . 5 . 7² = 52920

H) 77, 143, 247, 133 | 7

11, 143, 247, 19 | 11

1, 13, 247, 19 | 13

1, 1, 19, 19 | 19

1, 1, 1, 1 | 1

MMC = 7 . 11 . 13 . 19 = 19019

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