Question

Determine uma sequência de números quando
A) F(n)= 1/2 • N^2
B) F(n)= n^2 + 2
C) F(n)= n/2

Answer 1

Explicação passo-a-passo:

A) F(n)= 1/2 • n^2

$n = 0 = > f(0) = \frac{1}{2} \times {0}^{2} = 0$

$n = 1 = > f(1) = \frac{1}{2} \times {1}^{2} = \frac{1}{2}$

$n = 2 = > f(2) = \frac{1}{2} \times {2}^{2} = 2$

$n = 3 = > f(3) = \frac{1}{2} \times {3}^{2} = \frac{9}{2}$

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{0, 1/2, 2, 9/2,...}

B) F(n)= n^2 + 2

$n = 0 = > f(0) = {0}^{2} + 2 = 2$

$n = 1 = > f(1) = {1}^{2} + 2 = 3$

$n = 2 = > f(2) = {2}^{2} + 2 = 6$

$n = 3 = > f(3) = {3}^{2} + 2 = 11$

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{2, 3, 6, 11, ...}

C) F(n)= n/2

$n = 0 = > f(0) = \frac{0}{2} = 0$

$n = 1 = > f(1) = \frac{1}{2}$

$n = 2 = > f(2) = \frac{2}{2} = 1$

$n = 3 = > f(3) = \frac{3}{2}$

$n = 4 = > f(4) = \frac{4}{2} = 2$

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{0, 1/2, 1, 3/2, 2, ... }