Question

Determine uma PG de quatro termos, dados:
a) a1=3; q=2
b) a1=-16; q=1/2

Me respondam pfv?!
Obg

Answer 1

a) Pg (3,6,12,24)
a1=3
a2=3.2=6
a3=6.2=12
a4=12.2=24

b) Pg (-16, -8, -4, -2)
a1= -16
a2= $\frac{-16}{1} . \frac{1}{2} = \frac{-16}{2} = -8$
a3=$\frac{-8}{1}. \frac{1}{2} = \frac{-8}{2} = -4$
a4= $\frac{-4}{1}. \frac{1}{2} = \frac{-4}{2} = -2$

Answer 2

a) 3.6.12.24
b)-16-8-4-2